y^2+3y=7/4

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Solution for y^2+3y=7/4 equation: 


y in (-oo:+oo)

y^2+3*y = 7/4 // - 7/4

y^2+3*y-(7/4) = 0

y^2+3*y-7/4 = 0

y^2+3*y-7/4 = 0

DELTA = 3^2-(-7/4*1*4)

DELTA = 16

DELTA > 0

y = (16^(1/2)-3)/(1*2) or y = (-16^(1/2)-3)/(1*2)

y = 1/2 or y = -7/2

y in { -7/2, 1/2 }

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